Euler Problem 31

In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation:

1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).

It is possible to make £2 in the following way:

1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p

How many different ways can £2 be made using any number of coins?


In [1]:
count = [1] + [0]*200
coins = [1, 2, 5, 10, 20, 50, 100, 200]
for c in coins:
    for n in range(c, 201):
        count[n] += count[n-c]
print(count[200])


73682

In [ ]: